((x^2)/4)+x=5/4

Solution for ((x^2)/4)+x=5/4 equation:

((x^2)/4)+x=5/4

We move all terms to the left:

((x^2)/4)+x-(5/4)=0

We add all the numbers together, and all the variables

(x^2/4)+x-(+5/4)=0

We add all the numbers together, and all the variables

x+(x^2/4)-(+5/4)=0

We get rid of parentheses

x^2/4+x-5/4=0

We multiply all the terms by the denominator


x^2+x*4-5=0

Wy multiply elements

x^2+4x-5=0

a = 1; b = 4; c = -5;
Δ = b2-4ac
Δ = 42-4·1·(-5)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-6}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+6}{2*1}=\frac{2}{2}
=1
$